Curve and speed

Ben1337

Trainz operator
Hey there, I know this has already had a light shon on it and this thread does relate to http://forums.auran.com/trainz/showthread.php?t=33752&highlight=radius

In the aspect of this question: Is there a forula which calcalculate the optimum speed limit for curve radii or curve degree to give an optimised speed limit so that my trains don't de-rail on a curve ue to rounded up/rounded down figures to the nearest multiple of 5 for the curve degree?

In my aspect, lets say that I have a track with a radius of 128 meters and I wanted to find out a good speed for that curve.

So... I look onto http://forums.auran.com/trainz/showpost.php?p=367389&postcount=1 and find that the curve degree is about 13.67

But, curve degree means nothing to me, so I look on http://forums.auran.com/trainz/showpost.php?p=400225&postcount=5 but, I notice straight away is that the degree is in 5s and the speed goes up from 25 to 30 to 50 to 100.

In my eye, I look for precision (and, I admit, it's a headache trying to make things perfect.)

Besides, I have more speeds then just those 4 (not suprisingly, goes up in 5 MPHs from 5MPH to 125MPH).

So, I thought it would be easier to make it a forula, which can give me an about speed, a speed that takes advantage of the 25 different speed limits that are avalable to me.

I think the closest I ahve got to to amking a forula work for me is Speed Limit = 100/(Curve Degree +3.667)*4.667, which has both the 100MPH and 25.0MPH to the preferd accurasy.

Problem with mine is is that it gives vaules like 54MPH and 34MPH, which indicates that if my formula was put on a graph, the curve that it would produce wouldn't be steep enough for my perferance, so if the Curve Degree rose above 15, the MPH would be lower then the predicted speed, it is also prefered to get it as accurate as possible.

As you can see, I have had a fair go at it, and failed, I wondered if I could get some guidence into solving this problem.

Sorry if this post is a bit long-winded.
 
Hello Ben,

You might find this site helpful even though it give US FRA standards http://en.wikipedia.org/wiki/Speed_limits_in_the_United_States_(rail)

The formula contained there gives maximum speed for any curve of given degrees of curvature taking into account both compensated and uncompensated superelevation (banking, I think, in British parlance), so you won't be hampered by the limitations of the speed chart you are using now.

Bernie
 
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By formula, you mean this one
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?
 
Thanks for that - a very handy formula. The challenge is calculating the degree of curvature per 100 feet. Easy enough to guess it I suppose...

Andy :)
 
Can't find the link but I remember looking on an Indian railway website which stated as a broad rule, for uncompensated (no cant), curves divide the radius in metres by 5 and that = the speed in km/h. So for the OP's 128m radius curve that comes out at around 25 km/h (or 16 MPH).
 
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